json.fields
(Redirected from Json.fields)
json.fields() Function
• Introduced in version 1.3b49
Returns the fields (keys) for a JSON Object or the indexes for a JSON Array as a string list. The type of the value returned depends on the delimiter parameter.
Note: Because JSON Objects are unordered, json.fields will not reflect the order they were set in.
Usage
json.fields(jobj)
json.fields(jobj, delim)
Parameters
delim
=unspecified
: a standard string list is returned, with its default","
delimiter."json"
: a JSON Array is returned."x"
: a string list is returned with"x"
used as a delimiter.
Example
[h: a=json.fromStrProp("a=1;b=44;c=12")]
[r: json.fields(a)]
Returns
a,b,c
[h: a=json.fromList("a,1,g,4")]
[r: json.fields(a,";")]
Returns
0;1;2;3
[h: a=json.fromStrProp("a=1;b=44;c=12")]
[r: json.fields(a, "json")]
Returns
["a","b","c"]